8u^2+5u=0

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Solution for 8u^2+5u=0 equation:



8u^2+5u=0
a = 8; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·8·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*8}=\frac{-10}{16} =-5/8 $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*8}=\frac{0}{16} =0 $

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